Y=-2x^2+300x

Solution for Y=-2x^2+300x equation:

=-2Y^2+300Y

We move all terms to the left:

-(-2Y^2+300Y)=0

We get rid of parentheses

2Y^2-300Y=0

a = 2; b = -300; c = 0;
Δ = b2-4ac
Δ = -3002-4·2·0
Δ = 90000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{90000}=300$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-300}{2*2}=\frac{0}{4}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+300}{2*2}=\frac{600}{4}
=150
$